Math, asked by bouribishal67, 10 months ago

sin12°-cos78°+sin78°-cos12°=?

Answers

Answered by ashwani117117

0

Answer:

sin12°-cos(90°-12°)+sin(90°-12°)-cos12°=sin 12°-sin12°+cos12°-cos12°=0

Answered by Anonymous

0

sol:

sin12° - cos78° + sin78° - cos12

= (sin12° + sin78) - (cos78 + cos12)

= (sin90°) - (cos90°)

= ( 1) - (0)

= 1 - 0

= 1

Ans.= sin12° - cos78° + sin78° - cos12°= 1.

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