Question

sin12°-cos78°+sin78°-cos12°=?​

Answer 1

Answer:

sin12°-cos(90°-12°)+sin(90°-12°)-cos12°=sin 12°-sin12°+cos12°-cos12°=0

Answer 2

sol:

sin12° - cos78° + sin78° - cos12

= (sin12° + sin78) - (cos78 + cos12)

= (sin90°) - (cos90°)

= ( 1) - (0)

= 1 - 0

= 1

Ans.= sin12° - cos78° + sin78° - cos12°= 1.