sin15°=√3-1/2√2 solve this question please
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sin 15°=sin(60°-45°)
=sin60°cos 45°-cos 60°sin45°
=(√3/2)×(1/√2)-(1/2)×(1/√2)
=(√3/2√2)-(1/2√2)
=(√3-1)/2√2
siliverisrinivas:
good spred
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