Math, asked by shivgangadeshmukh999, 1 month ago

sin19°×cos71°+cos19°×sin71°

Answers

Answered by swapnodeep2556

2

Answer:

sin19° × cos71° + cos19° × sin71°

sin19° × cos(90° - 19°) + cos19° × sin(90° - 19°)

sin19° × sin19° + cos19° × cos19° [cos(90-x) =

sinx & sin(90°-x) =

cosx]

sin^2 19° + cos^2 19°

= 1

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