Question

Sin19°Cos11° + Sin71°Sin11°

Answer 1

Answer:

1*2

Step-by-step explanation:

Sin19°Cos11° + Sin71°Sin11°

=> Sin19°Cos11° + Sin(90-19°)Sin11°

we know,

sin(90-x) = cosx

= Sin19°Cos11° + Cos19°Sin11°

we know,

SinAcosB + CosASinB = Sin(A+B)

= Sin(19°+11°)= Sin(30) = 1/2

Answered by GauthMath.