Question

sin2 0 (where 0 € R ) =
​

Answer 1

Answer:

2θ = nπ, where, n = 0, ± 1, ± 2, ± 3,……., [Since, we know that θ = nπ, n ∈ Z is the general solution of the given equation sin θ = 0]

⇒ θ = nπ2nπ2, where, n = 0, ± 1, ± 2, ± 3,…….

Therefore, the general solution of the equation sin 2θ = 0 is θ = nπ2nπ2, where, n = 0, ± 1, ± 2, ± 3,…….

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