Question

sin²θ - ( 1 - cos²θ ) = 
$sin²θ - ( 1 - cos²θ ) =$
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Answer 1

${sin}^{2} \theta - (1 - {cos}^{2} \theta) \\ = {sin}^{2} \theta - {sin}^{2} \theta \\ = 0 \\ \\ \: we \: know \: {sin}^{2} \theta + {cos}^{2} \theta = 1$