Question

sin2 11º-cos2 79° = 0​

Answer 1

Answer:

Because of Trigonometric ratios for complementary angles

Step-by-step explanation:

$LHS=sin^{2} 11-cos^{2} 79\\=sin^{2} 11-cos^{2}(90-11)\\\\=sin^{2} 11-sin^{2} 11=0\\\\Therefore LHS=RHS$

Answer 2

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