sin² 28° - cos²62° = 0
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Answered by
5
hope this might help u
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afzalfarazp6cceu:
Cos 0° = 1
Answered by
4
LHS = sin^2 28°- sin^2(90-62)°
sin^2 28°- sin^2 28°
== 0
so
LHS = RHS
sin^2 28°- sin^2 28°
== 0
so
LHS = RHS
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