Question

sin2 28° + sin2 62° – tan2 45°​

Answer 1

$2( \cos ^{2} 28\% - \sin ^{2} 62\%$

$2( \cos ^{2}(90\% - 62\%) - \sin ^{2}62\%$

$2( \sin ^{2} 62\% - \sin ^{2} 62\%)$

$0$

Answer 2

Answer:

2(cos 2 28%−sin 2 62%

2( \cos ^{2}(90\% - 62\%) - \sin ^{2}62\% 2(cos 2

(90%−62%)−sin 2 62%

2( \sin ^{2} 62\% - \sin ^{2} 62\%)2(sin 2 62%−sin 2 62%)

0