sin2 29 + sin 2 61 =?
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Answered by
179
Answer :
We should know a few trigonometric identity rules before solving the problem l.
Here, sin (90 - θ) = cosθ
cos (90 - θ) = sinθ
Now, sin²29 + sin²61
= (sin29)² + sin²61
= {sin (90 - 61)}² + sin²61
= (cos61)² + sin²61
= cos²61 + sin²61
= 1,
since sin²θ + cos²θ = 1
#MarkAsBrainliest
We should know a few trigonometric identity rules before solving the problem l.
Here, sin (90 - θ) = cosθ
cos (90 - θ) = sinθ
Now, sin²29 + sin²61
= (sin29)² + sin²61
= {sin (90 - 61)}² + sin²61
= (cos61)² + sin²61
= cos²61 + sin²61
= 1,
since sin²θ + cos²θ = 1
#MarkAsBrainliest
Answered by
52
sin² 29° + sin² 61
sin² (90 - 61) + sin² 61
we know, sin(90 - ∅) = cos ∅
cos² 61 + sin² 61
we know, sin²∅+cos²∅= 1
Hence,
cos²61 + sin² 61 = 1
sin² (90 - 61) + sin² 61
we know, sin(90 - ∅) = cos ∅
cos² 61 + sin² 61
we know, sin²∅+cos²∅= 1
Hence,
cos²61 + sin² 61 = 1
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