Question

sin2 30° + cos2 60 + tan2 45​

Answer 1

The value of given expression is 2.

Step-by-step explanation:

we have to evaluate

2\tan^2 45^{\circ}+\cos^2 30^{\circ}-\sin^2 60^{\circ}2tan245∘+cos230∘−sin260∘

\tan 45^{\circ}=1tan45∘=1

\cos 30^{\circ}=\frac{\sqrt3}{2}cos30∘=23

\sin 60^{\circ}=\frac{\sqrt3}{2}sin60∘=23

2\tan^2 45^{\circ}+\cos^2 30^{\circ}-\sin^2 60^{\circ}2tan245∘+cos230∘−sin260∘

2(1)^2+(\frac{\sqrt3}{2})^2-(\frac{\sqrt3}{2})^22(1)2+(23)2−(23)2

2+\frac{3}{4}-\frac{3}{4}2+43−43

22

The value of given expression is 2

hope it helps you....