Question

sin2 30° - cos260° is​

Answer 1

The value of $\sin^{2} 30\degree - \cos^{2} 60\degree$ is zero(0).

Step-by-step explanation:

We have,

$\sin^{2} 30\degree - \cos^{2} 60\degree$

[ since, $\sin\ 30 =\dfrac{1}{2} and \cos\ 60 =\dfrac{1}{2}$]

=$(\frac{1}{2} )^{2} - (\frac{1}{2} )^{2}$

=$\dfrac{1}{4} -\dfrac{1}{4}$

= 0

Hence, the value of $\sin^{2} 30\degree - \cos^{2} 60\degree$ is zero

(0).

Answer 2

Step-by-step explanation:

The value of \sin^{2} 30\degree - \cos^{2} 60\degreesin

2

30°−cos

2

60° is zero(0).

Step-by-step explanation:

We have,

\sin^{2} 30\degree - \cos^{2} 60\degreesin

2

30°−cos

2

60°

[ since, \sin\ 30 =\dfrac{1}{2} and \cos\ 60 =\dfrac{1}{2}sin 30=

2

1

andcos 60=

2

1

=(\frac{1}{2} )^{2} - (\frac{1}{2} )^{2}(

2

1

)

2

−(

2

1

)

2

=\dfrac{1}{4} -\dfrac{1}{4}

4

1

−

4

1

= 0

Hence, the value of \sin^{2} 30\degree - \cos^{2} 60\degreesin

2

30°−cos

2

60° is zero

(0).