Math, asked by husenreang, 11 months ago

(Sin2 45°-Sin2 30°) (Cos2 60°-Sin2 30°) (tan2 45°-tan2 30°) /Sin2 45°+Sin2 30°+Cos2 60°+tan2 45°+tan2 30°​

Answers

Answered by azizalasha
4

Answer:

Step-by-step explanation:

N =  (Sin2 45°-Sin2 30°) (Cos2 60°-Sin2 30°) (tan2 45°-tan2 30°) /Sin2 45°+Sin2 30°+Cos2 60°+tan2 45°+tan2 30°​

= (Sin90°-Sin60°) (Cos120°-Sin60°) (tan90°-tan60°) /Sin90°+Sin60°+Cos120°+tan90°+tan60°​

= (1-√3/2) (-1/2-√3/2°) (∞ -√3°) /1+√3/2-1/2+1+√3

= ∞

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