Question

sin² 48º + sin²42º = 1 without using trigonometric table prove that​

Answer 1

Answer:

sin²48° + sin²42°=1

L.H.S = sin²48° + sin²42°

= sin²90°

= 1²

= 1

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Answer 2

QUESTION⇣⇣

prove that sin² 48º + sin²42º = 1.

ANSWER⇣⇣

$\mathbb\pink{L.H.S}$

$sin{(90 - 42)}^{2} + {sin}^{2} 42$

${cos}^{2} 42 \: + \: {sin}^{2} 42$

$: \longrightarrow \purple{1}$

R.H.S

$\dag{FORMULA \: \: USED:::-}$

$\blue{{sin}^{2} \theta \: + {cos}^{2} \theta \: = 1 }$

$\blue{sin(90 - theta) = cos \theta}$

$\dag{HOPE \: IT \: HELPS}\dag$

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