Question

sin²π\6+cos²π\5-tan²π\4=-1/2​

Answer 1

Answer:

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Step-by-step explanation:

sin^2(π/6)+cos^2(π/3)-tan^2(π/4)

= sin^2(180/6)+cos^2(180/3)-tan^2(180/4)

= sin^2(30)+cos^2(60)-tan^2(45)

= (1/2)^2+(1/2)^2-(1)^2

= 1/4+1/4–1

= 1/2–1

= -1/2 ans.