Question

Sin² 60+ cos² 60 = 1​

Answer 1

Step-by-step explanation:

(√3/2)^2+( 1/2)^2=1

3/4 + 1/4=1

now take lcm

3+1/4

4/4

=1

1=1

hence LHS=RHS.....

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Answer 2

Answer:

${sin}^{2} 60 + {cos}^{2} 60$

$({ \sqrt{3} \div 2})^{2} +( {1 \div 2})^{2}$

${3} \div 4 + 1 \div 4$

$\frac{ 3 + 1 }{4}$

$\frac{4}{4}$

$1$

since sin 60 = root over 3 by 2

and cos 60= 1by2

Hope this helps you