Question

Sin² 75° - Sin² 15°​

Answer 1

i think answer is 73....

Answer 2

Step-by-step explanation:

applying, a²-b²=(a+b)(a-b)

then applying,

i) sinC+sinD= 2sin(C+D/2)cos(C-D/2)

ii) sinC-sinD= 2cos(C+D/2)sin(C-D/2)

we will get,

2sin(90/2)cos(60/2).2cos(90/2)sin(60/2) =

$\frac{ \sqrt{3} }{4}$