Question

sin²(π/8) + sin²(3π/8) + sin²(5π/3) + sin²(7π/8). what would be the answer.​

Answer 1

Step-by-step explanation:

sin²(π/8) + sin²(3π/8) + sin²(5π/8) + sin²(7π/8)

= sin²(π/8) + sin²(3π/8) + sin²(π/2 + π/8) + sin²(π/2 + 3π/8)

= sin²(π/8) + sin²(3π/8) + cos²(π/8) + cos²(3π/8)

= [sin²(π/8) + cos²(π/8)] + [sin²(3π/8) + cos²(3π/8)]

= 1 + 1

= 2

Answer 2

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