sin²(π/8) + sin²(3π/8) + sin²(5π/3) + sin²(7π/8). what would be the answer.
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Answered by
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Step-by-step explanation:
sin²(π/8) + sin²(3π/8) + sin²(5π/8) + sin²(7π/8)
= sin²(π/8) + sin²(3π/8) + sin²(π/2 + π/8) + sin²(π/2 + 3π/8)
= sin²(π/8) + sin²(3π/8) + cos²(π/8) + cos²(3π/8)
= [sin²(π/8) + cos²(π/8)] + [sin²(3π/8) + cos²(3π/8)]
= 1 + 1
= 2
Answered by
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Sofia I forgot where are you from??
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