Math, asked by krishnavenidandupati, 6 months ago

sin2 85° + sin2 80° + sin2 10° + sin2 5° =2​

Answers

Answered by pandya97
0

Answer:

1/2

Step-by-step explanation:

sin (85+80+10+5)

sin 180

sin 150+30

sin 30

1/2

Answered by Anonymous
5

{ \tt{ \large{Question \colon}}}

{ \rm{ {sin}^{2}85° + {sin}^{2} 80° + {sin}^{2}10°+{sin}^{2}5° = 2}}

{ \tt{ \large{Solution \colon}}}

{ \rm{ {sin}^{2}85° + {sin}^{2} 80° + {sin}^{2}10°</p><p>+{sin}^{2}5° = 2}}

{ \rm{  = {sin}^{2}  85° +  {sin}^{2}5° +  {sin}^{2}80° +  {sin}^{2}  10° }}

{ \rm{  = {sin}^{2}  85° +  {sin}^{2}(90° - 85°) +  {sin}^{2}80° +  {sin}^{2}  (90° - 80°)}}

{ \rm{  = {sin}^{2}  85° +  {cos}^{2}85° +  {sin}^{2}80° +  {cos}^{2}   80°}}

{ \rm{  = ({sin}^{2}  85° +  {cos}^{2}85° )+  ({sin}^{2}80° +  {cos}^{2}   80°)}}

{ \rm{   = 1 + 1 = 2}}

 {\rm{ \therefore L.H.S. = R.H.S.}}

──────────────────────────

{ \rm{(i) {sin}^{2}  \theta +  {cos}^{2}  \theta = 1}}

{ \rm{(ii) {sec}^{2}  \theta  -   {tan}^{2}  \theta = 1}}

{ \rm{(iii) {cosec}^{2}  \theta  -   {cot}^{2}  \theta = 1}}

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