Question

) sin2 A - cos2 B = sin2 B - cos2 A​

Answer 1

$LHS = sin^{2} A - cos^{2} B \\= (1 - cos^{2} A ) - ( 1 - sin^{2} B )\\= 1 - cos^{2} A - 1 +sin^{2} B \\= sin^{2} B - cos^{2} A \\= RHS$

Therefore.,

$\red {sin^{2} A - cos^{2} B}\green {=sin^{2} B - cos^{2} A}$

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