Question

sin2θ=cos(θ−6
∘
) Find theta

Answer 1

Answer:

sin2θ=cos(θ−6°)

⇒cos(90−2θ)=cos(θ−6°)

⇒(90−2θ)=(θ−6°)

⇒3θ=96°

⇒θ=32°