sin²∅
----- + cos∅ = sec ∅
cos∅
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Solution==>
sin²A/cos²A+cos²A=secA
Solving L.H.S
sin²A/cos²A+cos²A
sinA(sinA)/cosA+ cosA
tanA.sinA+cos²A
tanA. sinA+1-sin²A
tanA+1
secA=R.H.S
hence proved
<====>
Identities used
(i) sin²A=1-cos²A
(ii)sec²A=tan²A+1
harjotsinghbhinder13:
are bhai thanks to boldo , solve kr kae diya hai aur isko galat mat samajna
sahi hai answer
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Answer:
Step-by-step explanation:
I think the question is sin2theta+ cos2theta= sectheta×costheta
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no the question given is correct as i have taken it from my geometry textbook shall i send you the picture of it????
Yes please
um.. how shall i send you??
wait let me post again with a picture ohk?
you can check it by going on my profile
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