Question

Sin²Α+Cos²Α=? *........​

Answer 1

Answer:

1

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Step-by-step explanation:

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Answer 2

If cos²α – sin²α = tan²β, then the value of cos²β – sin²β is

cot²α

cot²α

tan²α

tan²α

Correct Option: C

cos²α – sin²α = tan²β

⇒ cos²α – (1 – cos²α) = tan²β

⇒ 2cos²α – 1 = tan²β

⇒ 2cos²α = 1 + tan²β = sec²β

⇒ cos²β =12cos²α

sin²β = 1 – cos²β

= 1 -12cos²α

=2cos²α - 12cos²α

∴ cos²β – sin²β

=1-

2cos²α - 12cos²α2cos²α

=1 - 2cos²α + 12cos²α

=2(1 - cos²α)=

sin²α2cos²αcos²α

= tan²α

=1

Step-by-step explanation:

Answer is 1