Question

sin2 theta + 5cos2 theta + 2 = 4cos theta + 3​

Answer 1

Answer:

Given, sin

2

θ+5cos

2

θ=4,

⇒1−cos

2

θ+5cos

2

θ=4

⇒4cos

2

θ = 3

Solving we get cosθ=

2

3

So θ=30

∘

Now secθ+cosecθ = sec(30)

∘

+cosec(30)

∘

=

3

2

+2