sin2 theta + cos 2 theta. =
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TO PROVE :
SIN² THETA + COS² THETA = 1
SOLUTION:
Let a, b, c be lengths of right angled triangle
By definition
sinθ=b/c( opposite side/ hypotenuse)
cosθ=a/c( adjacent side/ hypotenuse)
sin² θ+cos² θ= (b²/c²)+(a²/c²) = (a²+b²)/c²
From Pythagoras theorem
c²= a² + b²
∴ ( a²+b² ) /c² = 1
Hence, sin²θ+cos² θ=1
Hence, proved.
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