Question

sin² theta + cos⁴ theta = cos² theta + sin⁴ theta​

Answer 1

Answer:

$\huge\underline\mathfrak\green{ᴀɴSᴡᴇʀ}$

$\longrightarrow$LHS = ( sin⁴∅ -cos⁴∅)

$\longrightarrow$( sin²∅ -cos²∅)(cos²∅ +sin²∅)

we know ,

$\longrightarrow$sin²∅ + cos²∅ = 1

$\longrightarrow$(sin²∅ -cos²∅).1 = RHS

Answer 2

Answer:

⟶ LHS = ( sin⁴∅ -cos⁴∅)

\longrightarrow⟶ ( sin²∅ -cos²∅)(cos²∅ +sin²∅)

we know ,

\longrightarrow⟶ sin²∅ + cos²∅ = 1

\longrightarrow⟶ (sin²∅ -cos²∅).1 = RHS