sin2 theta in terms of tan
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Answer:
sin 2A = 2tanA1+tan2A
Step-by-step explanation:
sin 2A = 2 sin A cos A
⇒ sin 2A = 2 sinAcosA ∙ cos2 A
⇒ sin 2A = 2 tan A ∙ 1sec2A
⇒ sin 2A = 2tanA1+tan2A
There for sin 2A = 2tanA / 1+tan2A
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