Question

sin² theta = (x²+y²+1)/2x. find value of x and y​

Answer 1

Answer:

Answer: (3) 1

Solution:

Given,

sin2θ = (x2 + y2 + 1)/2x

We know that 0 ≤ sin2θ ≤ 1.

Now consider (x2 + y2 + 1)/2x ≤ 1

x2 + y2 + 1 ≤ 2x

x2 + y2 + 1 – 2x ≤ 0

(x – 1)2 + y2 ≤ 0

Thus, x – 1 = 0, y = 0

x = 1, y= 0.