sin2 thita
1+cos 2thita=tan thita
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Step-by-step explanation:
sin2θ(1+cos2θ)=tanθ
2sinθcosθ(1+2cos^2θ-1)=tanθ
2sinθcosθ(2cos^2θ)=sinθ/cosθ
4cos^4θ=1
cosθ=1/√2
θ=45°
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