Question

sin²0/cos²0 + cos²0/sin²0 = sec²0 - cosec²0 - 2​

Answer 1

$\tt{ {\dfrac{sin^2 \theta}{cos^2 \theta}} + {\dfrac{cos^2 \theta}{sin^2 \theta}} }$

${\boxed{\tt{tan^2 \theta = {\dfrac{sin^2 \theta}{cos^2 \theta}}}}}$

${\boxed{\tt{cot^2 \theta = {\dfrac{cos^2 \theta}{sin^2 \theta}}}}}$

$\tt{\implies tan^2 \theta + cot^2 \theta}$

${\boxed{\tt{1 + tan^2 \theta = sec^2 \theta}}}$

${\boxed{\tt{1 + cot^2 \theta = cosec^2 \theta}}}$

$\tt{\implies sec^2 \theta - 1 + cosec^2 \theta - 1}$

$\tt{\implies sec^2 \theta + cosec^2 \theta - 2}$