Math, asked by madhupadma, 1 year ago

sin20⁰ tana sec70⁰≈√3

Answers

Answered by TPS
0
sin20\ *\ tan\ a\ *\ sec\ 70= \sqrt{3}  \\  \\ sin20\ *\ tan\ a\ *\  \frac{1}{cos\ 70} = \sqrt{3}   \\  \\ sin20\ *\ tan\ a\ *\  \frac{1}{sin\ (90-70)} = \sqrt{3}   \\  \\ sin20\ *\ tan\ a\ *\  \frac{1}{sin\ 20} = \sqrt{3}

tan\ a= \sqrt{3}  \\  \\ a=tan^{-1} \sqrt{3}=60^{0}
Answered by kvnmurty
0
Sin 20\ Tan\ a\ \frac{1}{Cos\ 70}=\sqrt3\\\\tan\ a\ \frac{Sin\ 20}{Sin(90-70)}=\sqrt3\\tan\ a=\sqrt3\\a=\pi/3\ \ or\ \ 4\pi/3\\\\a=n\pi+\pi/3,\ \ n\ is\ any\ integer
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