Sin20sin40+sin60sin80
aastha15das:
how is my answer
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Answered by
2
sin20. sin 40. sin60. sin80
=> sin60[sin20.sin40.sin80]
=>√3/2[sin20.sin(60-20).sin(60+20)]
=>√3/2[sin 3(20)/4]
=>√3/2[sin 60/4]
=>√3/2[√3/2*4]
=>√3/2*√3/8
=3/16
hope it's help u
=> sin60[sin20.sin40.sin80]
=>√3/2[sin20.sin(60-20).sin(60+20)]
=>√3/2[sin 3(20)/4]
=>√3/2[sin 60/4]
=>√3/2[√3/2*4]
=>√3/2*√3/8
=3/16
hope it's help u
Answered by
4
DEAR STUDENT,
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
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