Math, asked by simar060105, 1 year ago

(sin²22+sin²68)÷(cos²22+cos²68) +sin²63+cos63sin27 ​

Answers

Answered by igdfvbjkgf
8

1÷1+1

2

your answer is 2

Answered by arunbanuganesh090
28

Answer:

Step-by-step explanation:

= (sin²22+sin²68)/(cos²22+cos²68) + sin²63 + cos63 x sin27

= (sin²22 + cos²(90-22))/ (cos²22 +sin²(90-22)) + sin²63 + cos63 x cos(90-27)

= (sin²22 + cos²22) / (cos²22 +sin²22) + sin²63 + cos²63

= 1/1 + 1

= 1 + 1

= 2

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