Question

sin²34°+sin²56°+2tan18°tan72°-cot²30°​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

${ \sin(34) }^{2} + { \sin(90 - 34) }^{2} + 2 \tan(18) \tan(90 - 18) - { \cot(30) }^{2} \\ = { \sin(34) }^{2} + { \cos(34) }^{2} + 2 \tan(18) \cot(18) - { \cot(30) }^{2} \\ = 1 + 2 - 3 \\ = 0$