Question

Sin²38⁰ + sin²52⁰ please answer ​

Answer 1

Answer:

1

Step-by-step explanation:

Given :

Sin ²38⁰ + Sin ²52⁰

To find :

The value of the given expression

Solution :

We know that,

$\boxed{\sin x = \cos (90-x)}$

So,

$\longmapsto \sin52^{\circ} = \cos(90-52)^{\circ} = \cos38^{\circ}$

Now, rewriting the question with the values, we get,

$\implies \sin^238^{\circ} + \cos^238^{\circ}$

We know that,

$\boxed {\mathrm {\sin^2 x+ \cos^2x = 1}}$

So,  we get,

$\implies \underline {\sin^238^{\circ} + \cos^238^{\circ}} }$

$\implies \huge{\texttt{\underline {\underline{1}}}}$

Hope it helps!!