Question

sin24+sin55-sin125+sin204-sin330

Answer 1

Hope u like my process
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Formula to be used
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$= > \bf \: \sin(180 - x) = \sin(x) \\ \\ = > \bf \: \sin(180 + x) = - \sin(x) \\ \\ = > \bf \: \sin(360 - x) = - \sin(x)$
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$= > \bf \sin(24) + \sin(55) - \sin(125) + \sin(204) - \sin(330) \\ \\ = \sin(24) + \sin(55) - \sin(180 - 55) + \sin(180 + 24) - \sin(360 - 30) \\ \\ = \sin(24) + \sin(55) - \sin(55) - \sin(24) - (- \sin(30) ) \\ \\ = \bf \: \sin(30) = \frac{1}{2} = 0.5$
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