Question

sin25/sec65 + cos25/cosec65

Answer 1

[tex] \frac{sin 25}{sec65} + \frac{cos25}{cosec65} = \frac{sin25}{ cosec(90-65) } + \frac{cos25}{sec(90-65)} = \frac{sin25}{ \frac{1}{sin25} } + \frac{cos25}{ \frac{1}{cos25} } [/tex]
=$sin^{2}25+cos^{2}25 = 1$

Answer 2

Hope it helps:)
Pls mark as brainliest:)