sin25+sin32+sin204+sin212=
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Answered by
5
sin 24 + sin 32 + sin 204 + sin 212
= sin 24 + sin 32 + sin (180+24) + sin (180 +32)
= sin 24 + sin 32 - sin 24 - 2in 32
=0
= sin 24 + sin 32 + sin (180+24) + sin (180 +32)
= sin 24 + sin 32 - sin 24 - 2in 32
=0
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1
sin25° + sin32° +sin204° +sin212° = ?
= sin25° + sin32° +sin (180 + 24 ) + Sin ( 180° + 32°)
= Sin25° + sin32° + sin24° + 2Sin32 = 0
= sin25° + sin32° +sin (180 + 24 ) + Sin ( 180° + 32°)
= Sin25° + sin32° + sin24° + 2Sin32 = 0
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