Math, asked by Aartiraju, 1 year ago

Sin²5°+sin²10°+sin²15°+........sin²90° =? ?

Answers

Answered by TheLifeRacer
71
Hey !!!!

Here is ur answer ....

from LHS

sin²5° +sin²10° + sin²15° +.........sin²90°

= (sin²5° + sin²85° )+(sin²10°+sin²80°) +....+(sin²40° +sin²50° )+sin²45° +sin²90°

= [sin²5° +sin²(90°-5°)] +[sin²10°+sin²(90°-10°)]+....+[sin²40° +sin²(90°-40°)] +sin245° +sin²90°

= (sin²5° +cos²5° ) +(sin²10°+cos²10°)+....+(sin²40° +cos²40°)+sin²45°+sin²90°

=1+1+1+1+1+1+1+1+(1/√2)²+1

=9+1/2

=] 9+1/2 =19/2 Answer ...

hope it helps !!

#Rajukumar111

Aartiraju: thanks Rajukumar11
YASHIKAJINDAL: wrong
YASHIKAJINDAL: there will be 8 on the place of 9
YASHIKAJINDAL: 5,10,15,20,25,30,35,40 will make pair so these are 8 only
Answered by hashman01
5

Then answer is

19/2

Follow me if it helps

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