Question

sin²60+tan²45/cosec²30​

Answer 1

Step-by-step explanation:

${sin}^{2} 60 + \frac{ {tan}^{2} 45}{{cosec}^{2}30 }$

$= ( { \frac{ \sqrt{3} }{2} )}^{2} + \frac{( {1)}^{2} }{( {2)}^{2} }$

$= \frac{3}{4} + \frac{1}{4}$

$= \frac{3 + 1}{4}$

$= \frac{4}{4}$

$= 1$