Math, asked by shreyvasisth3478, 10 months ago

Sin28°54/sec61°6+cos28°54/cosec61°6​

Answers

Answered by Anonymous
1

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Answer:

sec61°6'=1/cos61°6'

cosec61°6'=1/sin61°6'

sin(a+b)=sin(a)cos(b)+cos(a)+sin(b)

above equations can be written by,

sin28°54'cos61°6'+cos28°54'sin61°6'

sin(28°54'+61°6')=sin(90°)=1

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