Math, asked by akanshasharma26, 11 months ago

Sin²A + 1/1+Tan²A =1​

Answers

Answered by sharmaman900
1

Answer:

sin^{2} A + 1/1+tan^{2} A = sin^{2} A +  1/sec^{2}A =  sin^{2} A + cos^{2} A = 1

Step-by-step explanation:

Basic identities are used here in solving this question.

1 + tan^{2}A = sec^{2}A \\ sin^{2}A + cos^{2}A = 1\\

1/secA = cosA

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