Math, asked by shaikahamadhussia, 3 months ago

sin2A/1-cosA.1_cosA/cosA=TanA/2

Answers

Answered by parthsail399

1

Answer:

According to question,

secA+tanA1−cosA1=cosA1−secA−tanA1

⟹secA+tanA1+secA−tanA1=2secA

Solving LHS,

⟹(secA+tanA)(secA−tanA)secA−tanA+secA+tanA

⟹sec2A−tan2A2secA

⟹12secA

⟹2secA = RHS

Hence proved

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