Math, asked by shravaniemmewar, 7 months ago

Sin²a/1+cot²a + tan²a/(1+tan²a)²+cos²a

Answers

Answered by yuditak
0

Answer:

cos^2a

Step-by-step explanation:

sin^2a/1+cot^2a+tan^2a/(1+tan^2a)^2+cos^2a

change the value(sin^2a/1+cot^2a)

(1/cosec a×1/cosec a)/cosec^2a

(1/cosec^2a)/cosec^2a

1/cosec^2a×cosec^2a/1

cut the cosec^2a and we get the value=1

change the value of 1+tan _ _ .....

1+tan^2a(1+tan^2a)^2+cos^2a

1+(sina/cosa×sina/cosa)/sec^4a+cos^2a

1+(sin^2a/cos^2a)/1/cosa×1/cosa×1/cosa×1/cos+cos^2a)

1+(sin^2a/cos^2a)/1/cos^2a

1+sin^2a

cos^2a

HOPE YOU UNDERSTAND THIS.

Similar questions