sin2A=2sinA prove
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sin(2A) = sin(A + A)
As sin(a + b) = sinacosb + sinbcosa,
sin(A + A) = sinAcosA + sinAcosA
Therefore sin(2A) = 2sinAcosA
ashi6644:
nahi aaya samajh
Answered by
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Heya!!
MISTAKE IN UR QUESTION
QUESTION SHOULD BE LIKE THIS
PROVE THAT Sin2A = 2 Sin A × Cos A
PROOF
L.H.S
Sin 2A = Sin ( A + A ) = Sin A Cos A + Cos A Sin A
= 2 Sin A × Cos A
HENCE PROVED.
MISTAKE IN UR QUESTION
QUESTION SHOULD BE LIKE THIS
PROVE THAT Sin2A = 2 Sin A × Cos A
PROOF
L.H.S
Sin 2A = Sin ( A + A ) = Sin A Cos A + Cos A Sin A
= 2 Sin A × Cos A
HENCE PROVED.
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