sin2A=2sinA when cosA=?
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Hey there !!!
In trigonometry
sin2X=2sinXcosX----------------------Identity 1
Given :
sin2A=2sinA---------------------Equaiton 1
But according to Identity 1 eqaution 1 must be
sin2A=2sinAcosA--------------------Eqaution 2
So, from equation 1 and 2 we get
2sinA=2sinAcosA
⇒⇒⇒⇒1=cosA
Therefore
cosA=1 and A=0°
Hope this helps you............
In trigonometry
sin2X=2sinXcosX----------------------Identity 1
Given :
sin2A=2sinA---------------------Equaiton 1
But according to Identity 1 eqaution 1 must be
sin2A=2sinAcosA--------------------Eqaution 2
So, from equation 1 and 2 we get
2sinA=2sinAcosA
⇒⇒⇒⇒1=cosA
Therefore
cosA=1 and A=0°
Hope this helps you............
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