Question

sin2A = 2sinA where A is 30 how it can solve step by step pls​

Answer 1

Answer:

Here A is the angle (thita)

sin2A=2sinA.cosA

sin2A=2sin30.cos30. (A=30)

sin2A=2×1/2.√3/2. (sin30=1/2,,cos30=√3/2)

sin2A=1×√3/2

sin2A=√3/2