Question

(sin²a)³ +(cos²a)³=1-3sin²acos²a

Answer 1

Answer:

(sin²a)³+(cos²a)³=1-3sin²a.cos²a

Step-by-step explanation:

L.H.S

(sin²a)³+(cos²a)³

=(sin²a+cos²a)³+3 sin²a.cos²a(sin²a+cos²)

=(1)³+3sin²a.cos²a(1)

=1+3sin²a.cos²a

L.H.S=R.H.S. PROVED

HOPE IT HELPS

Answer 2

Answer:

Step-by-step explanation:

L.H.S.

(Sin^2a )^3 + (cos^2a)^3

= By (a+b)^3= a^3+b^3 + 3ab(a+b)

= (a+b)^3 -3ab(a+b) =a^3+b^3

So

=(Sin^2a+cos^a)^3 -3×sin^2a×cos^2a(sin^2a+cos^2a)

=(1)^3 -3×sin^2a×cos^2a(1)

= 1 - 3sin^2a×cos^2a

Hence L.H.S. = R.H.S.