sin2A=4/5. Find tanA
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Heya !!!
Sin²A = 4/5
SinA = ✓4/5
SinA = 2/✓5 = P/H
P = 2 and H = ✓5
By Pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)²
(B)² = (✓5)² - (2)²
(B)² = 5-4
B = ✓1 = 1
TanA = P/B
TanA = 2/1 = 2
★ HOPE IT WILL HELP YOU ★
Sin²A = 4/5
SinA = ✓4/5
SinA = 2/✓5 = P/H
P = 2 and H = ✓5
By Pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)²
(B)² = (✓5)² - (2)²
(B)² = 5-4
B = ✓1 = 1
TanA = P/B
TanA = 2/1 = 2
★ HOPE IT WILL HELP YOU ★
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