Question

sin2A-cos2A= 2*sin2A-1

Answer 1

Answer:

∴ Sin2A – Cos2A = 2a/( a2 + 1) – (a2 – 1)/( a2 + 1) = (2a – a2 + 1)/(a2 + 1)

Answer 2

Answer:

Proper question:
$\sin ( 2a ) - \cos ( 2a ) = 2 \sin ( 2a ) -1$

Step-by-step explanation:

A=$\pi$$n_{1}$$+$$\frac{\pi }{4} ,n_{1}$∈$Z$
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